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1969 CONCACAF Championship qualification

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A total of 9 CONCACAF teams entered the competition,[1] eventually reduced to 8 after Haiti renounced.[2] Later on, Haiti tried to join again but the late application was rejected.[3] Honduras, El Salvador and the USA[4] did not enter.
Costa Rica (as the hosts), Guatemala (as the defending champions), the Netherlands Antilles and Trinidad and Tobago qualified automatically. Play-offs were arranged for the remaining two spots.[5]

Preliminary round

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Series One

 Mexico3–0Bermuda 
Mancilla 6', 30'
Langarica 52'

Mexico qualifies with aggregate score of 4-2.

Series Two

 Jamaica1–1Panama 
Ziadie (pen.) Tapia 46'
Panama 1–2 Jamaica
Espinoza 20' Largie 27'
Hill 85'

Jamaica qualifies with aggregate score of 3-2.

Teams qualified to the 1969 CONCACAF Championship

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References

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